Calculate normative material loss of heat carrier (water) from cylindrical pipe according to rule 10.1.2 of Minenergo Order 325.
Usage
m325nvl(a = 0, d = 720, wth = 12, len = 1)
m325nml(
temperature = 130,
pressure = mpa_kgf(6),
a = 0,
d = 720,
wth = 12,
len = 1
)Arguments
- a
heat carrier (water) volume loss factor of cylindrical pipe, [h⁻¹]. Type:
assert_double.- d
nominal (outside) diameter of pipe, [mm]. Type:
assert_double.- wth
nominal wall thickness of pipe, [mm]. Type:
assert_double.- len
pipe length, [m]. Type:
assert_double.- temperature
temperature of heat carrier (water) inside the pipe, [°C]. Type:
assert_double.- pressure
absolute pressure of heat carrier (water) inside the pipe, [MPa]. Type:
assert_double.
Value
-
For
m325nvl volume loss of heat carrier per hour, [m³/h].
-
For
m325nml mass loss of heat carrier per hour, [ton/h].
Type: assert_double.
Details
The calculations are based on the a-factor, which may be treated as the maximum allowed rate of heat carrier (water) volume loss per hour. So, its value varies from 0.0 h⁻¹ (no loss of heat carrier) up to 0.0025 h⁻¹ (maximum possible loss allowed). The cylindrical form of pipe is always assumed in calculations.
See also
Other Minenergo:
m278hlair(),
m278hlcha(),
m278hlund(),
m278insdata,
m278inshcm(),
m278soildata,
m325beta(),
m325nhl(),
m325nhldata,
m325nxdata
Examples
library(pipenostics)
# According to Minenergo-325 it may be granted to loose right up to the next
# value of tons of heat carrier (water) per year (nine-month heating season)
# for the typical supplying 100-meter length pipe:
m325nml(a = 0.0025, len = 100) * 24 * 90
#> [1] 192.0934